) In the Haber process for ammonia, K = 0.036 for the reaction N2(g) + 3H2(g)...

) In the Haber process for ammonia, K = 0.036 for the reaction N2(g) + 3H2(g) ⇔ 2NH3(g) at 50K. If a reactor is charged with partial pressures of 0.020 bar of N2 and 0.020 bar of H2, what will be the equilibrium partial pressure of (a) N2; (b) H2; and (c) NH3? Enter the answers in bar to two significant figures and do not enter the units.

Expert Solution

N2(g) + 3H2(g) ⇔ 2NH3(g)

I 0.02 0.02 0

C -x -3x 2x

E 0.02-x 0.02-3x 2x

KP = PNH3^2/PN2PH2^3

0.036 = (2x)^2/(0.02-x)(0.02-3x)

0.036*(0.02-x)(0.02-3x) = 4x²

x = 0.0016

PH2 = 0.02-3x = 0.02-3*0.0016 = 0.0152bar

PN2 = 0.02-x = 0.02-0.0016 = 0.0184bar

PNH3 = 2x = 2*0.0016bar = 0.0032bar

queen_honey_blossom answered 2 years ago

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