In: Math
Researchers conducted a study to investigate the effectiveness
of two different treatments for depression (Lithium or...
Researchers conducted a study to investigate the effectiveness
of two different treatments for depression (Lithium or Imipramine).
A sample of individuals diagnosed with bipolar depression were
divided into three groups - one group received Lithium, one group
received Imipramine, and the last group was given a placebo. After
a specified length of time, patients are evaluated for a recurrence
of depression. Use StatCrunch to conduct a chi-square test to
determine if recurrence is related to the treatment prescribed. In
StatCrunch, select Stat > Tables > Contingency > With
Data. Select one of the variables of interest for the row variable
and the second variable as the column variable. Then click
Compute.
- Select the appropriate hypotheses:
- HoHo: recurrence of depression is related to the treatment
prescribed
HaHa: recurrence of depression is not related to the treatment
prescribed
- HoHo: recurrence of depression is not related to the treatment
prescribed
HaHa: recurrence of depression is related to the treatment
prescribed
- TS: χ2χ2 = (round to 4 decimal places)
- probability = (round to 4 decimal
places)
- Conclusion: At the 0.10 level, there Select an answer is is
not significant evidence to conclude recurrence of
depression Select an answer is not is related to the
treatment prescribed.
Throwback Question: Suppose we know that the
risk of liver cancer among alcoholics without cirrhosis of the
liver is 29.8%. A researcher conjectures that the risk of cancer
among alcoholics with cirrhosis of the liver is higher. Suppose we
sample 81 alcoholics with cirrhosis of the liver and determine 29
have liver cancer. Use this information to answer the
following:
- For each person in the sample, what variable is recorded?
- number of years diagnosed with cirrhosis
- level of alcoholism
- percentage of individuals with liver cancer
- if the individual has liver cancer
- Completely describe the sampling distribution
for the sample proportion of alcoholics with cirrhosis who have
liver cancer when samples of size 81 are selected (assuming there
is no difference in occurrence between those with and without
cirrhosis).
- mean: μˆpμp^ =
- standard deviation: σˆpσp^ = (round to 4 decimal
places)
- shape: the distribution of the sample proportion is Select an
answer not normally distributed normally
distributed
- Checks: np = and n(1 - p) =
- Test the appropriate claim using the data collected at a
significance level of 0.10.
- HoHo : p ? < > = ≠ HaHa : p ? =
< > ≠
- αα =
- TS: z = (round your final answer to 2 decimal
places; carry 4 decimal places throughout your calculation)
- probability = (round to four decimal
places)
- Decision: Select an answer fail to reject H₀ reject H₀
- Interpretation:At the 0.10 level, there Select an answer is is
not significant evidence to support the claim that
the incidence rate of liver cancer is Select an answer lower higher
different than in alcoholics diagnosed with
cirrhosis.