In: Math
To study the effectiveness of possible treatments for
insomnia, a sleep researcher
conducted a study with 12 participants. Four participants were
instructed to count
sheep (the Sheep Condition), four were told to concentrate on their
breathing (the
Breathing Condition), and four were not given any special
instructions. Over the next
few days, measures were taken how long it took each participant to
fall asleep. The
average times for the participants in the Sheep Condition were 14,
28, 27, and 31; for
those in the Breathing Condition, 25, 22, 17, and 14; and for those
in the control
condition, 45, 33, 30, and 41. Do these results suggest that the
different techniques have
different effects? Answer the question by conducting a hypothesis
test at the 0.05
significant level.
Use the five steps of hypothesis testing and demonstrate your
calculations.
Please demonstrate all calculations in detail in your answers including how you found the standard deviations. Thanks.
Summarizing sleep time in excel:
Sleep time condition wise | ||
Sheep | Breathing | Control |
14 | 25 | 45 |
28 | 22 | 33 |
27 | 17 | 30 |
31 | 14 | 41 |
This study requires ANOVA:
ANOVA output by excel:
SUMMARY | ||||||
Groups | Count | Sum | Average | Variance | ||
Sheep | 4 | 100 | 25 | 56.66667 | ||
Breathing | 4 | 78 | 19.5 | 24.33333 | ||
Control | 4 | 149 | 37.25 | 48.25 | ||
ANOVA | ||||||
Source of Variation | SS | df | MS | F | P-value | F crit |
Between Groups | 660.5 | 2 | 330.25 | 7.665377 | 0.011387 | 4.256495 |
Within Groups | 387.75 | 9 | 43.08333 | |||
Total | 1048.25 | 11 |
Null hypothesis: different techniques doesn't have different effects
Alternate hypothesis: different techniques does have different effects
significant level. = 0.05
Our p-value from ANOVA = 0.011387 which is less than 0.05
Hence we reject Null hypothesis meaning different techniques does have different effects.
ANOVA calculations are quite complex and time consuming. Hence done via excel.