A particle leaves the origin with initial velocity v⃗ =15i^+18j^m/s v→o=15i^+18j^m/s, undergoing constant acceleration a⃗ =−1.5i^+0.31j^m/s2a→=−1.5i^+0.31j^m/s2....

A particle leaves the origin with initial velocity v⃗ =15i^+18j^m/s v→o=15i^+18j^m/s,

undergoing constant acceleration a⃗ =−1.5i^+0.31j^m/s2a→=−1.5i^+0.31j^m/s2.

in what direction is it moving ?

Expert Solution

genius_generous answered 2 years ago

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