Question

A survey on the number of hours a college student works per week showed that the hours varied from 5 to 61 where 5 was the lowest number and 61 was the highest number. Determine the class width, classes, class marks and class boundaries of a frequency distribution table if the work hours were grouped using 8 classes. You can make a table to help you do this. Note: there is no frequency column.

Answer 1

Answer :

We are given that,

A survey on the number of hours a college student works per week showed that the hours varied from 5 to 61 where 5 was the lowest number and 61 was the highest number. We want to, determine the class width, classes, class marks and class boundaries of a frequency distribution table if the work hours were grouped using 8 classes.

Frequency Distribution Table :

Classes	class mark=(lower limit + upper limit)/2	class boundaries=actual class limit
5 - 12	(5 + 12)/2 =8.5	(5, 12)
12 - 19	(12 + 19)/2 = 15.5	(12,19)
19 - 26	(19 + 26)/2 = 22.5	(19,26)
26 - 33	(26 + 33)/2 = 29.5	(26,33)
33 - 40	(33 + 40)/2 = 36.5	(33,40)
40 - 47	(40 + 47)/2 = 43.5	(40,47)
47 - 54	(47 + 54)/2 = 50.5	(47,54)
54 - 61	(54 + 61)/2 = 57.5	(54,61)

Class width =

Class width refers to the difference between the upper and lower boundaries of any class.

OR

Class width =

The difference between the upper limits of two consecutive (neighboring) classes, or

The difference between the lower limits of two consecutive classes.

So,

Class width = 12 - 5 = 7