Question

In: Statistics and Probability

A survey was conducted at a college to determine the number of hours students spent outside...

A survey was conducted at a college to determine the number of hours students spent outside on weekends during the winter. For students from cold weather climates, the results were M = 8, SD = 1.5. For students from warm-weather climates, the results were M = 5, SD = 4.2. Explain what these numbers mean to a person who has never had a course in statistics, and suggest conclusions the person can draw from these results. These conclusions use the means, raw scores, and variability in in your explanations.

View keyboard shortcuts12pt

Paragraph

If playing video games and aggression are correlated, give two REASONS that explain why we cannot infer causality from this correlation? Describe how each limits causality. Explain a situation (explicitly) that is a slight exception to one of the reasons.  

View keyboard shortcuts12pt

Paragraph

Solutions

Expert Solution


Related Solutions

A study was conducted to determine if the number of hours spent studying for an exam...
A study was conducted to determine if the number of hours spent studying for an exam is associated with the exam score. The following are the observations obtained from a random sample of 5 students: Number of Hours Spent Studying (X) 8 2 6 4 2 Exam Score (Y) 98 74 87 82 72 The average number of hours spent studying for an exam is _____. Part A: A) 82.6 B) 22 C) 4.4 D) 413 The average exam score...
A nationwide survey of college students was conducted and found that students spend two hours per...
A nationwide survey of college students was conducted and found that students spend two hours per class hour studying. A professor at your university wants to determine whether the time students spend at your university is significantly different from the two hours. A random sample of 36 statistics students is carried out and the findings indicate an average of 1.75 hours. Assume a populatoin standard deviation of 0.5 hours. Using a level of significance of 0.05: 1. Construct a 95%...
A survey of 200 college students showed the distribution of the number of hours of TV...
A survey of 200 college students showed the distribution of the number of hours of TV watched per week. The mean was found to be 3.66 hours with a standard deviation of 4.93. Assume the normal model is appropriate. Find the number of hours of TV watched by top 25% of college students.
A study was conducted to determine if students in different college years differ on the number...
A study was conducted to determine if students in different college years differ on the number of hours of sleep they obtain. On a specified mid-semester Wednesday morning 25 Freshmen, 25 Sophomore, 25 Junior and 25 Senior college students reported the number of Hours of Sleep they had obtained on the previous evening. Answer the following question referring to the following tables. Descriptive Statistics Year Mean Std. Deviation N Freshmen 7.7080 1.86881 25 sophomore 7.1600 1.34412 25 Junior 7.4400 1.47422...
A study conducted by the MLC on campus found the number of hours spent at the...
A study conducted by the MLC on campus found the number of hours spent at the MLC during a week. The distribution of times spent at the MLC is normally distributed with an average of 75 minutes and a standard deviation of 18 minutes. (a) If a single student that uses the MLC is selected at random, what is the probability that this student spent between 80 and 100 minutes at the MLC that week? (b) Now if a sample...
The number of hours 10 students spent studying for a test and their scores on that...
The number of hours 10 students spent studying for a test and their scores on that test is represented in the table below. Hours spent studying, x 0 2 4 5 5 5 6 7 8 9 Test scores, y 40 51 64 69 73 75 93 90 95 95 7) What amount of the variance in test score (y) do the hours spent studying (x) account for this sample? (r2 =?) Interpret the result in the context of the...
The number of hours 1010 students spent studying for a test and their scores on that...
The number of hours 1010 students spent studying for a test and their scores on that test are shown in the table. Is there enough evidence to conclude that there is a significant linear correlation between the​ data? Use alphaαequals=0.050.05. ​ Hours, x 00 11 22 44 44 55 55 66 77 88 Test​ score, y 4141 4040 5555 5656 6464 6666 7575 7878 8181 9797 LOADING... Click here to view a table of critical values for​ Student's t-distribution. Setup...
The number of hours 10 students spent studying for a test and their scores on that...
The number of hours 10 students spent studying for a test and their scores on that test are shown in the table. Is there enough evidence to conclude that there is a significant linear correlation between the data? Use alphaequals0.05. Hours, x= 0 1 2 4 4 5 5 6 7 8 Test score, y= 41 40 51 56 65 70 76 70 84 97 1. Setup the hypothesis for the test. 2. Identify the critical value(s). Select the correct...
The number of hours 10 students spent studying for a test and their scores on that...
The number of hours 10 students spent studying for a test and their scores on that test is represented in the table below. Hours spent studying, x 0 2 4 5 5 5 6 7 8 9 Test scores, y 40 51 64 69 73 75 93 90 95 95 3) Describe the type of correlation and interpret the correlation in the context of the data. Be specific in describing the magnitude, direction, and strength of the relationship. (12p) 4)...
The number of hours 10 students spent studying for a test and their scores on that...
The number of hours 10 students spent studying for a test and their scores on that test are shown in the table. Is there enough evidence to conclude that there is a significant linear correlation between the​ data? Use alphaαequals= .01 X(hours) = top row; Y(score)=bottom row 0 1 2 3 4 4 5 6 7 8 41 46 52 50 65 68 75 85 82 91 Set up hypothesis test = ?? Critical Values = ?? Calculate test statistic;...
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT