Question

In: Statistics and Probability

The National Survey of Student Engagement reported that the mean number of hours spent studying per...

The National Survey of Student Engagement reported that the mean number of hours spent studying per week for nursing majors is 18. Suppose a medical researcher obtained a random sample of 100 nursing majors, which yielded a sample mean study time of 19 19 hours. Assume the population standard deviation σ=10 hours. Test, using level of significance ?=0.05, whether the population mean study time for nursing majors is greater than 18 hours per week.

?crit=

Find the test statistic ?data.

?data=

Solutions

Expert Solution

Solution :

Given that,

Population mean = = 18

Sample mean = = 19

Population standard deviation = = 10

Sample size = n = 100

Level of significance = = 0.05

This is a rihgt tailed test.

The null and alternative hypothesis is,

Ho: 18

Ha: > 18

Critical value of  the significance level is α = 0.05, and the critical value for a right-tailed test is

= 1.645

The test statistics,

Z =( - )/ (/n)

= ( 19 - 18 ) / ( 10 / 100)

= 1

Since it is observed that z = 1 < = 1.645, it is then concluded that the null hypothesis is fails to reject.

Conclusion :

It is concluded that the null hypothesis Ho is fails to reject.. Therefore, there is enough evidence to claim that the population

mean μ is greater than 18, at the 0.05 significance level.


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