In: Chemistry
1) If the electron drops down from the n=5 level to n=2, and then to the ground state of hydrogen, what colors (wavelengths) of light will be emitted?
2) What color of light is this?
3) Photon color for n=2 to ground
4) What color of light is this?
Apply Rydberg Formula
E = R*(1/nf^2 – 1/ni ^2)
R = -2.178*10^-18 J
Nf = final stage/level
Ni = initial stage/level
E = Energy per unit (i.e. J/photon)
E = (-2.178*10^-18)*(1/5^2 – 1/2^2)
E = 4.573*10^-19
For the wavelength:
WL = h c / E
h = Planck Constant = 6.626*10^-34 J s
c = speed of particle (i.e. light) = 3*10^8 m/s
WL = (6.626*10^-34)(3*10^8)/( 4.573*10^-19 )
WL = 4.34681*10^-7 m
WL (in nm) = 4.34681*10^-7 *109 = 434 nm (this is violet/purple)
2)
the color of light is violet/purple
3)
now for n= 2 to n = 1
Apply Rydberg Formula
E = R*(1/nf^2 – 1/ni ^2)
R = -2.178*10^-18 J
Nf = final stage/level
Ni = initial stage/level
E = Energy per unit (i.e. J/photon)
E = (-2.178*10^-18)*(1/2^2 – 1/1^2)
E = 1.6335*10^-18
For the wavelength:
WL = h c / E
h = Planck Constant = 6.626*10^-34 J s
c = speed of particle (i.e. light) = 3*10^8 m/s
WL = (6.626*10^-34)(3*10^8)/( 1.6335*10^-18)
WL = 1.21689*10^-7 m
WL (in nm) = 4.34681*10^-7 *109 = 121 nm this is ultaviolet lgith
no visible light to human eye