Question

Which codes add 1 to integer n?

1) n=n+1;

2) n++;

3)++n;

4) n+=1;

5) n=--n+2

Answer 1

Which codes add 1 to integer n:

Answer: All of the above

(1) n=n+1; (2)  n++; (3) ++n; (4) n+=1; (5)  n=--n+2;

Description:

(1) n = n + 1;

• The above statement Simply adds 1 to integer n as "n + 1".

• Example: Let's take integer n = 6 and apply n = n + 1 in the code, this will give the result n = 7.

Code:

Output:

(2) n++;

• The above statement is postfix or post-increment operator that adds 1 to integer n as "n++". This operator follows a rule 'use-then-change' means that n will be incremented first and then assigned to variable.

• Example: Let's take integer n = 6 and apply n++ in the code, this will give the result n = 7.

Code:

Output:

(3) ++n;

• The above statement is prefix or pre-increment operator that adds 1 to integer n as "++n". This operator follows a rule 'change-then-use' means that n will be assigned first to variable and then gets incremented.

• Example: Let's take integer n = 6 and apply ++n in the code, this will give the result n = 7.

Code:

Output:

(4) n+=1;

• The above statement is arithmetic assignment operator that adds 1 to integer n as "n+=1", which is simply n = n + 1.

• Example: Let's take integer n = 6 and apply n+=1 in the code, this will give result n = 7.

Code:

Output:

(5) n = --n+2;

• The above statement uses pre-decrement operator (--n) that will first decrement the n value by 1 and then adds 2 to it as "n = --n+2".

• Example: Let's take integer n = 6 and apply n= --n+2 in the code, this will give the result n = 7.

Code:

Output: