For this question I must see the diagrams and all the calculations. In each case the...

For this question I must see the diagrams and all the calculations. In each case the answer alone will count 2 points.

All the % values are based on m/m that means 2% = 2kg/100kg.

How much of each of two solutions A and B must be mixed together with 18.5kg of a dry solid to make a final suspension of 2,150 kg containing 8.25% solids. Solution A contains 5.00% solids and solution B contains 11.00% solids.

Expert Solution

A suspension is a heterogeneous mixture in which solute-like particles settle out of a solvent-like phase some time after their introduction.

We apply the word 'suspension' when particles are big enough to eventually settle. If the particles are too small to ever settle, they are said to form a colloid.

We use the terms 'solute-like' and 'solvent-like,' because we are dealing with a heterogeneous mixture, while the terms solute and solvent refer to solutions, which are homogeneous.

Hello, as a result, I get a flux negative, I need you to do the drawing to kow what you want to do, nonetheless, the equation system is :

f1+f2+18.5kg = 2.150kg

0.05f1+0.11f2+18.5kg = 0.1773kg

getting as a result f1(A) and f2(B)

f1 = 333.754 kg

f2 = -350.104kg

this values are due to a bad specification of the exercise. Nonetheless, I had not into account R, if the exercise want to be solved I need another data because it is overspecified.

queen_honey_blossom answered 2 years ago

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