In: Statistics and Probability
Suppose you have a normal distribution with known mu = 5 and sigma =1.N(5,1). Use Z=scores to compute the probability that a value drawn from this distribution will be:
a.Greater than 4.5
b.Greater than 6.3
c.Less than 3
d.Between 3.5 and 6.5
e.Greater than 6 or less than 4
2)For each a---e above, plot an graph of the normal distribution and shade in the are a under the curve corresponding to the probability you reported.(NOTE: make a separate graph for each)
Part a)
P ( X > 4.5 ) = 1 - P ( X < 4.5 )
Standardizing the value
Z = ( 4.5 - 5 ) / 1
Z = -0.5
P ( Z > -0.5 )
P ( X > 4.5 ) = 1 - P ( Z < -0.5 )
P ( X > 4.5 ) = 1 - 0.3085
P ( X > 4.5 ) = 0.6915
Part b)
P ( X > 6.3 ) = 1 - P ( X < 6.3 )
Standardizing the value
Z = ( 6.3 - 5 ) / 1
Z = 1.3
P ( Z > 1.3 )
P ( X > 6.3 ) = 1 - P ( Z < 1.3 )
P ( X > 6.3 ) = 1 - 0.9032
P ( X > 6.3 ) = 0.0968
Part c)
P ( X < 3 )
Standardizing the value
Z = ( 3 - 5 ) / 1
Z = -2
P ( X < 3 ) = P ( Z < -2 )
P ( X < 3 ) = 0.0228
Part d)
P ( 3.5 < X < 6.5 )
Standardizing the value
Z = ( 3.5 - 5 ) / 1
Z = -1.5
Z = ( 6.5 - 5 ) / 1
Z = 1.5
P ( -1.5 < Z < 1.5 )
P ( 3.5 < X < 6.5 ) = P ( Z < 1.5 ) - P ( Z < -1.5
)
P ( 3.5 < X < 6.5 ) = 0.9332 - 0.0668
P ( 3.5 < X < 6.5 ) = 0.8664
e.Greater than 6 or less than 4
P ( 4 < X < 6 )
Standardizing the value
Z = ( 4 - 5 ) / 1
Z = -1
Z = ( 6 - 5 ) / 1
Z = 1
P ( -1 < Z < 1 )
P ( 4 < X < 6 ) = P ( Z < 1 ) - P ( Z < -1 )
P ( 4 < X < 6 ) = 0.8413 - 0.1587
P ( 4 < X < 6 ) = 0.6827
Required probability = 1 - 0.6827 = 0.3173