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In: Statistics and Probability

Giving a normal distribution with mean mu=40 and standard deviation sigma = 10 where the probability...

Giving a normal distribution with mean mu=40 and standard deviation sigma = 10 where the probability that x0<x<x1 = 0.9. What is the Total Area to the left for x1.

Expert Solution

Giving a normal distribution with mean mu=40 and standard deviation sigma = 10

where the probability that x0<x<x1 = 0.9.

What is the Total Area to the left for x1.

Here Area between x0 & x1 is 0.90

so P( x0 < x < x1 ) = 0.90

So from graph we can say that

P(x < x0) = 0.05

& P(x > x1) = 0.05

Area left to the x1 = P( x < x1 )

P(x < x1) = 1-P(x > x1)

= 1- 0.05

= 0.95

P(x < x1) = 0.95

Answer: Area left to the x1 is 0.95

OR

orchestra answered 2 years ago

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