In: Math
An exam is given to select the top 15% of incoming students for a special honors program. The cutscore for the exam is 28 points. The mean of the test scores is 24 points. What is the standard deviation of the test scores?
Solution:
Given: The cutscore for the top 15% students to the examination is 28 points.
Mean of test scores is 24.
That is 
We have to find the standard deviation of test scores.
Assuming normal distribution and using z score formula we can find the value of standard deviation.
Since for top 15% have cut score =28
Then find corresponding z value.
That is find z such that
P(Z>z)=0.15
That is find z such that
P(Z<z)=1-P(Z>z)
P(Z<z)=1-0.15
P(Z<z)=0.85
Look in z table for area 0.8500 or its closest area and find corresponding z value.

From Z table we get area 0.8508 is closest to 0.8500 and it corresponds to z=1.0 and 0.04
Thus z= 1.04
Now use z score formula





Thus the standard deviation of test scores is 