In: Chemistry
The decomposition of crystalline N2O5 N2O5(s)⟶2NO2(g)+12O(g) is an example of a reaction that is thermodynamically favored even though it absorbs heat. At 25 ∘C we have the following values for the standard state enthalpy and free energy changes of the reaction: ΔH∘=+109.6kJ/mol ΔG∘=−30.5kJ/mol
we know G = H - T S
from above G =−30.5kJ/mol H = 109.6kJ/mol T = 25 + 273 K = 298 K S = ?
−30.5kJ/mol = 109.6kJ/mol - 298 K S
−30.5kJ/mol - 109.6kJ/mol = - 298 K S
140.1 kJ/mol = 298 K S
S = 0.4701 kJ/mol k
in above raction as H =+ve it means that the value of - T S must be greater than H so that
0 > H - T S
and G = - ve so that the reaction must be spontaneous or thermodynamically favored .