The decomposition of N2O5 is described by the following equation. 2N2O5(g) → 4NO2(g) + O2(g) If...

The decomposition of N2O5 is described by the following equation. 2N2O5(g) → 4NO2(g) + O2(g) If the rate constant is 4.50 × 10−4 s−1, what is the half-life of this reaction? × 10 s in scientific notation

The reaction 2A → B is second order with a rate constant of 51.0/M·min at 24°C. (a) Starting with [A]0 = 9.30 × 10−3 M, how long will it take for [A]t = 2.90 × 10−3 M? min (b) Calculate the half-life of the reaction. min

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queen_honey_blossom answered 1 year ago

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the first order rate constant for the decomposition of N2O5, 2N2O5(g)->4NO2(g)+O2(g) at 70C is 6.82x10^-3 s^-1....

the first order rate constant for the decomposition of N2O5, 2N2O5(g)->4NO2(g)+O2(g) at 70C is 6.82x10^-3 s^-1. suppose we start with 3.00x10^-2 mol of N2O5(g) in a volume of 2.3L A) how many moles of N2O5 will remain after 3.0 min? B) how many minutes will it take for the quantity of N2O5 to drop to 1.7x10^-2 mol? C) what is the half-life of N2O5 at 70C?

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The first-order rate constant for the decomposition of N2O5, 2N2O5(g)→4NO2(g)+O2(g) at 70∘C is 6.82×10−3 s−1. Suppose...

The first-order rate constant for the decomposition of N2O5, 2N2O5(g)→4NO2(g)+O2(g) at 70∘C is 6.82×10−3 s−1. Suppose we start with 2.60×10−2 mol of N2O5(g) in a volume of 2.0 L . 1. How many moles of N2O5 will remain after 4.0 min ? 2. How many minutes will it take for the quantity of N2O5 to drop to 1.6×10−2 mol ? 3. What is the half-life of N2O5 at 70∘C?

The first-order rate constant for the decomposition of N2O5, 2N2O5(g)→4NO2(g)+O2(g) at 70∘C is 6.82×10−3 s−1. Suppose...

The first-order rate constant for the decomposition of N2O5, 2N2O5(g)→4NO2(g)+O2(g) at 70∘C is 6.82×10−3 s−1. Suppose we start with 2.80×10−2 mol of N2O5(g) in a volume of 2.2 L . How many moles of N2O5 will remain after 6.0 min ? How many minutes will it take for the quantity of N2O5 to drop to 1.6×10−2 mol ? What is the half-life of N2O5 at 70∘C?

In the gas phase, N2O5 decomposes according to the following reaction 2N2O5 (g) --> 4NO2 (g)...

In the gas phase, N2O5 decomposes according to the following reaction 2N2O5 (g) --> 4NO2 (g) + O2 (g) We put some N2O5 (g) in a container and it has a pressure of 0.154 atm. After the reaction proceeds for 103 seconds, the total pressure has increased to 0.260 atm. Assuming constant temperature and volume, the average rate of disappearance of the N2O5 (g) during this time interval is answer is: 1.0 x 10^-3 atm/s Please show work :D

For 2N2O5(g) = 4NO2(g) + O2(g) 1. Determine, by making the appropriate graphs, whether this decomposition reaction...

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