In: Chemistry
Show that 15M acid is approximately 90% acetic acid and 10% water by weight?
90% of acetic acid means 90 g of acetic acid (CH3COOH) present in 100 g of solution.
Molar mass of CH3COOH is = (2xatomic mass of C )+(2x atomic mass of O ) + (4x atomic mass of H)
= ( 2x12)+(2x16)+(4x1)
= 60 g mol-1
So number of moles of CH3COOH is
Since we have taken the percentage into consideration the total weight of the solution is 100g
Since the water has a density if 1 g/mL so the volume of the solution must be same number as that in grams
Therefore the volume of the solution is = 100 mL = 0.1 L
We know that
So it is proved