In: Chemistry
How many calcium atoms are in 33.8g of calcium?
Given mass of Calcium , m = 33.8 g
Molar mass of Calcium is , M = 40 g/mol
So number of moles of Calcium , n = mass/molar mass
= 33.8 g / 40 (g/mol)
= 0.845 moles
We know that 1 mole of any compound contains avagadro number ( 6.023 x 10 23 ) of atoms
So 1 mole of calcium contains 6.023 x 10 23 calcium atoms
0.845 moles of calcium contains Z calcium atoms
Therefore the number of calcium atoms are 5.09x10 23