Question

A load of bricks of mass M = 185 kg is attached to a crane by a cable of negligible mass and length L = 3.19 m. Initially, when the cable hangs vertically downward, the bricks are a horizontal distance D = 1.39 m from the wall where the bricks are to be placed. What is the magnitude of the horizontal force that must be applied to the load of bricks (without moving the crane) so that the bricks will rest directly above the wall?

Answer 1

Here is what I solved before, please modify the figures as per your question. Please let me know if you have further questions. If this helps then kindly rate 5-stars

A load of bricks of mass M = 167 kg is attached to a crane by a cable of negligible mass and length L = 3.05 m. Initially, when the cable hangs vertically downward, the bricks are a horizontal distance D = 1.17 m from the wall where the bricks are to be placed. What is the magnitude of the horizontal force that must be applied to the load of bricks (without moving the crane) so that the bricks will rest directly above the wall?

SOLUTION:

When the Bricks will rest above wall.. The cable would have tilted and a component of it will try to bring the load of bricks back to original position. so , that equivalent force must be applied.

Angle made by cable with vertical = tan^-1 D/L = 21

Let tension be T.

T cos 21 = Mg ---->>. T = 1753 N

Horizontal force = T sin 21 = 628 N