Question

In: Physics

A merry-go-round accelerates from rest to 0.74 rad/s in 34 s. Part A Assuming the merry-go-round...

A merry-go-round accelerates from rest to 0.74 rad/s in 34 s.

Part A

Assuming the merry-go-round is a uniform disk of radius 8.0 m and mass 3.20×104 kg , calculate the net torque required to accelerate it.

Express your answer to two significant figures and include the appropriate units

Solutions

Expert Solution

Initial angular speed of the merry-go-round = 1 = 0 rad/s (At rest)

Angular speed of the merry-go-round after 34 sec = 2 = 0.74 rad/s

Time period = T = 34 sec

Angular acceleration of the merry-go-round =

2 = 1 + T

0.74 = 0 + (34)

= 2.176 x 10-2 rad/s2

Mass of the merry-go-round = M = 3.2 x 104 kg

Radius of the merry-go-round = R = 8 m

Moment of inertia of the merry-go-round = I

I = MR2/2

I = (3.2x104)(8)2/2

I = 1.024 x 106 kg.m2

Net torque on the merry-go-round =

= I

= (1.024x106)(2.176x10-2)

= 2.2 x 104 N.m

A) Net torque required to accelerate the merry-go-round = 2.2 x 104 N.m


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