In: Physics
Given:-
Diameter,d=60cm
Radius,r=30cm=0.30m
wi=120 rpm =12.56 rad/s [1rpm=2*pie/60 rad/s]
wf=280 rpm = 29.31 rad/s
t= 4s
(a)
Use the kinematic equation, wf=wi+?t
we get ?= [wf-wi]/t = [29.31-12.56] / 4= 4.19 rad/s2
(b)
Radial component of acceleration , ar= v2/r =rw2
At t= 2s,
w=wi+?t=12.56+[4.19*2] = 20.93 rad/s
ar= rw2 = 0.30* 20.932 = 131.46 m/s2
Radial component of acceleration is 131.46 m/s2
Tangential component of acceleration, at=angular acceleration*radius
at= ?*r= 4.19* 0.30 = 1.26m/s2
Tangential component of acceleration is 1.26 m/s2
(c)
Use the kinematic equation, wf2=wi2+2??
we get ?=[ wf2-wi2] / 2? = [ 29.312-12.562] / 2*4.19= 83.69 rad= 13.33 revolutions [1revolution=2*pie radians]