Benzene has a ΔHvap = 33.90 kJ/mol and a ΔSvap = 96.4 J/mol-K. What is the...

Benzene has a ΔHvap = 33.90 kJ/mol and a ΔSvap = 96.4 J/mol-K. What is the vaporization temperature of Benzene in Celsius?

Expert Solution

Vaporization temperature, T_vap = ΔH_vap / ΔS_vap

Where T_vap is Vaporization themperatue in kelvin

Given ΔH_vap = 33.90 kJ/mol

= 33.90x10³ J/mol

ΔS_vap = 96.4 J/(mol-K)

Plug the values we get T_vap = ΔH_vap / ΔS_vap

= (33.90x10³ J/mol) / (96.4 J/(mol-K) )

= 351.6 K

= 351.6 - 273 ^oC

= 78.6 ^oC

Therefore the vaporization temperature of Benzene is 78.6 ^oC

queen_honey_blossom answered 5 months ago

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