In: Chemistry
Benzene has a ΔHvap = 33.90 kJ/mol and a ΔSvap = 96.4 J/mol-K. What is the vaporization temperature of Benzene in Celsius?
Vaporization temperature, Tvap = ΔHvap / ΔSvap
Where Tvap is Vaporization themperatue in kelvin
Given ΔHvap = 33.90 kJ/mol
= 33.90x103 J/mol
ΔSvap = 96.4 J/(mol-K)
Plug the values we get Tvap = ΔHvap / ΔSvap
= (33.90x103 J/mol) / (96.4 J/(mol-K) )
= 351.6 K
= 351.6 - 273 oC
= 78.6 oC
Therefore the vaporization temperature of Benzene is 78.6 oC