Question
In: Advanced Math
Solve the LP problem using graphical method. Determine the optimal values of the decision variables and...
Solve the LP problem using graphical method. Determine the optimal values of the decision variables and compute the objective function.
Maximize Z = 2A + 10B
Subject to
10A + 4B ≥ 40
A + 6B ≥ 24
A + 2B ≤ 14
A, B ≥ 0
with soln pls thank you!
Solutions
Colby Messinger answered 2 years agoRelated Solutions
For the following LP problem, determine the optimal solution by the graphical solution method. Min Z=...
For the following LP problem, determine the optimal solution by
the graphical solution method.
Min Z= 3x1+2x2
Subject to 2x1+x2 >10
-3x1+2x2
< 6
X1+x2
> 6
X1,x1
> 0
Graph and shade the feasible region
Solve this linear programming (LP) problem using the transportation method. Find the optimal transportation plan and...
Solve this linear programming (LP) problem using the
transportation method. Find the optimal transportation plan and the
minimum cost. (Leave no cells blank - be certain to enter
"0" wherever required. Omit the "$" sign in your
response.)
Minimize
8x11
+
2x12 + 5x13 +
2x21 + x22
+ 3x23 +
7x31 + 2x32 +
6x33
Subject to
x11 + x12 +
x13
=
90
x21 + x22 +
x23
=
105
x31 + x32 +
x33
=
105
x11...
Solve the following LP problem using graphical solution method. MAX: 5 X1 + 3 X2 Subject...
Solve the following LP problem using graphical solution method.
MAX: 5 X1 + 3 X2 Subject to: 2 X1 − 1 X2 ≤ 2 6 X1 + 6 X2 ≥ 12 1 X1
+ 3 X2 ≤ 5 X1, X2 ≥ 0
Identify the type of optimal solution for the following LP problems by the graphical solution method....
Identify the type of
optimal solution for the following LP problems by the graphical
solution method. Show your work
(1) Min 2X1 +
3X2
S.T. 2X1 - 2X2
<= 2
-2X1 +
X2 <= 1
X1 => 0, X2 => 0
If the objective function of the above formulation is changed
from Min 2X1 + 3X2 to Max
2X1 + 3X2, what type of
optimal solution does this problem provide? Note that all
constraints remain...
Find the optimal values of x and y using the graphical solution method: Max x +...
Find the optimal values of x and y using the graphical solution
method: Max x + 5y subject to: x + y ≤ 5 2x + y ≤ 8 x + 2y ≤ 8 x ≥
0, y ≥ 0
For the following linear programming problem, determine the optimal solution by the graphical solution method Max...
For the following linear programming problem, determine the optimal
solution by the graphical solution method
Max
-x + 2y
s.t.
6x - 2y <= 3
-2x + 3y <= 6
x + y <= 3
x, y
>= 0
solve the following LP. Formulate and algebraically solve the problem. what is the new optimal z...
solve the following LP. Formulate and algebraically solve the
problem.
what is the new optimal z value
show that the current basis is optimal
max z=65x1+25x2+20x3
8x1+6x2+x3<=48
4x1+2x2+1.5x3<=20
2x1+1.5x2+0.5x3<=8
x2<=5
x1,x2,x3>=0
Solve the LP problem. If no optimal solution exists because there is no Solution Set, enter...
Solve the LP problem. If no optimal solution exists because
there is no Solution Set, enter EMPTY. If no optimal solution
exists because the region is unbounded, enter UNBOUNDED.
Note that an unbounded region can still have an optimal
solution while a bounded region is guaranteed to have optimal
solutions. HINT [See Example 1.]
Maximize and minimize p = x + 2y subject
to
x
+
y
≥
4
x
+
y
≤
10
x
−
y
≤
4
x...
Solve the LP problem. If no optimal solution exists because there is no Solution Set, enter...
Solve the LP problem. If no optimal solution exists because
there is no Solution Set, enter EMPTY. If no optimal solution
exists because the region is unbounded, enter UNBOUNDED.
Note that an unbounded region can still have an optimal
solution while a bounded region is guaranteed to have optimal
solutions. HINT [See Example 1.]
Minimize c = 2x − 2y subject to
x
6
≤
y
y
≤
2x
3
x
+
y
≥
10
x
+
2y
≤
35...
Situation: Construct the Dual and solve the Dual by the graphical and simplex method. The values...
Situation:
Construct the Dual and solve the Dual by the graphical and
simplex method. The values of the variables are in the table.
Minimize Z =
Ax1 + Bx2 + Cx3
Subject to:
Dx1 + Ex2 + Fx3 >= J
Gx1 + Hx3 + Ix3 >= K
x1, x2, and x3 >= 0
Student
Coefficients
Numbers
A
B
C
D
E
F
G
H
I
J
K
Objective Function
Equations
Constant recursor
1
2
1
1
3
5
2...
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