In: Chemistry
which of the following have the same numbers of atoms as 55.8 grams of Fe
55.8g He, 32g O2, 32g O3, 16g O
no of atoms = mass of substance*6.023*1023/Gram atomic weight
= 55.8*6.023*1023/56 = 6.023*1023 atoms
no of atoms = mass of substance*6.023*1023/Gram atomic weight
= 55.8*6.023*1023/4
= 13.91*1023 atoms
no of atoms = mass of substance*6.023*1023 *atomicity/Gram molecular weight
= 32*6.023*1023 *2/32 = 12.046*1023 atoms
no of atoms = mass of substance*6.023*1023 *atomicity/Gram molecular weight
= 32*6.023*1023 *3/48 = 12.046*1023 atoms
no of atoms = mass of substance*6.023*1023/Gram atomic weight
= 16*6.023*1023/16 = 6.023*1023 atoms
same no of atoms present in 32g O2, 32g O3
same no of atoms present in 55.8 grams of Fe,16g O