Find the pH after 15.00 mL of 0.100 M HCl has been added to 25.00 mL...

Find the pH after 15.00 mL of 0.100 M HCl has been added to 25.00 mL of 0.100 M NH3 solution. Assume volumes are additive.

Expert Solution

HCl + NH3 -----------------> NH4Cl

15 x0.1 25 x0.1 0

1.5 2.5 0 ------------initial

0 1.0 1.5 ------------ after reaction

NH3 and NH4Cl mixture remained . it can act as buffer

Kb of NH3 = 1.8 x10^-5

pKb= -logKb= 4.74

pOH = pKb + log [salt/base]

= 4.74 + log[1.5/1]

= 4.916

PH= 14-pOH= 14-4.916

pH = 9.083

queen_honey_blossom answered 1 month ago

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