A diverging lens (f = –11.0 cm) is located 24.0 cm to the left of a...

A diverging lens (f = –11.0 cm) is located 24.0 cm to the left of a converging lens (f = 35.0 cm). A 3.00-cm-tall object stands to the left of the diverging lens, exactly at its focal point. (a) Determine the distance of the final image relative to the converging lens. (b) What is the height of the final image?

Expert Solution

genius_generous answered 2 years ago

A converging lens (f1 = 24.0 cm) is located 56.0 cm to the left of a...

A converging lens (f1 = 24.0 cm) is located 56.0 cm to the left of a diverging lens (f2 = -28.0 cm). An object is placed to the left of the converging lens, and the final image produced by the two-lens combination lies 20.4 cm to the left of the diverging lens. How far is the object from the converging lens? do1 =

An object is placed 22.7 cm to the left of a diverging lens (f = -13.0...

An object is placed 22.7 cm to the left of a diverging lens (f = -13.0 cm). A concave mirror (f = 9.99 cm) is placed 29.9 cm to the right of the lens to form an image of the first image formed by the lens. Find the final image distance, measured relative to the mirror. (b) Is the final image real or virtual? (c) Is the final image upright or inverted with respect to the original object?

An object is placed 27.2 cm to the left of a diverging lens (f = -10.6...

An object is placed 27.2 cm to the left of a diverging lens (f = -10.6 cm). A concave mirror (f = 17.1 cm) is placed 40.3 cm to the right of the lens to form an image of the first image formed by the lens. Find the final image distance, measured relative to the mirror. (b) Is the final image real or virtual? (c) Is the final image upright or inverted with respect to the original object?

A 1.8-cm-tall object is 3.1 cm to the left of a diverging lens with a focal...

A 1.8-cm-tall object is 3.1 cm to the left of a diverging lens with a focal length of -3.1 cm. A converging lens with a focal length of 4.6 cm is distance d to the right of the first lens. a) For what value of d is the image at infinity? b) What is the angular size of the image as seen by looking through the converging lens? ?c) What is the angular magnification of this two-lens magnifier?

A diverging lens (f = -20cm) is placed 10cm to the left of a plane mirror....

A diverging lens (f = -20cm) is placed 10cm to the left of a plane mirror. A match stick is placed 25cm to the left of the lens. (I) Where is the final image of the stick? (II) Is the image real or virtual? Upright or inverted? (III) What is the magnification? (IV) Where is the final image relative to the mirror?

A diverging lens of focal length -12.5 cm is placed 40.0 cm from a converging lens...

A diverging lens of focal length -12.5 cm is placed 40.0 cm from a converging lens of unknown focal length. A 15.2 cm tall erect object is placed 25.3 cm in front of the diverging lens which is to produce an image on a screen that is twice the size of the original object but inverted. A) Where should the screen be located to produce a clear image? Give the distance from the converging lens to the screen in cm. B)...

1.20cm tall object is 50.0cm to the left of a diverging lens (lens 1) of focal...

1.20cm tall object is 50.0cm to the left of a diverging lens (lens 1) of focal length of magnitude 40.0cm. A second converging lens (lens 2) of focal length 60.0cm, is located 300cm to the right of the first lens along the same optic axis. (a)Calculate the location of the image (call it I1) formed by the lens1. (b) Is image I1 real or virtual? (c) Is image I1 on left side or right side of lens 1? (d) Calculate...

A 1.4-cm-tall object is located 3.0cm to the left of a converging lens with a focal...

A 1.4-cm-tall object is located 3.0cm to the left of a converging lens with a focal length of 4.0cm . A diverging lens, of focal length -7.4cm, is 14cm to the right of the first lens. Find the position of the final image. s2` = -5.7 cm Find the size of the final image. h2` = ? Find the orientation of the final image. a) real, upright b) real, inverted c) virtual, upright d) virtual, inverted

An object is located to the left of a convex lens whose focal length is f=34...

An object is located to the left of a convex lens whose focal length is f=34 cm. The magnification (m) produced by the lens is 4.0. Find an expression for magnification in terms of “f” and object distance (do). To increase the magnification to 5.0, calculate the distance through which the object should be moved. Also explain your result with free hand ray diagram. At what position of the object the magnification becomes infinity?

Problem 1) A 5 cm tall object is 20 cm in front of a diverging lens...

Problem 1) A 5 cm tall object is 20 cm in front of a diverging lens with a focal length of 10 cm. a) What is the location of the image? -6.67cm b) What is the height of the image? -1.67 cm c) The image is:virtual d) The image is:upright At 15 cm to the right of the lens in problem 1 we add a converging lens with a focal length of 10 cm. a) What is the location of...

Question