1.20cm tall object is 50.0cm to the left of a diverging lens (lens 1) of focal...

1.20cm tall object is 50.0cm to the left of a diverging lens (lens 1) of focal length of magnitude 40.0cm. A second converging lens (lens 2) of focal length 60.0cm, is located 300cm to the right of the first lens along the same optic axis.

(a)Calculate the location of the image (call it I1) formed by the lens1.

(b) Is image I1 real or virtual?

(d) Calculate magnification m1 of lens 1. Is image I1 upright or inverted?

(e) Calculate height of the image I1.

(f) I1 is now the object for the second lens. Is the object for lens 2 real or virtual?

(g) Calculate the object distance for lens 2?

(h) Calculate the location of the image I2 produced by lens2.

(i) Calculate magnification m2 of lens2. Is image I2 upright or inverted?

(j) Calculate height of the image I2.

(k) Find overall magnification of these two lens system.

(l) Is final image real or virtual?

(m) Is final image upright or inverted, relative to initial object?

(n) Is final image enlarged or reduced in size, relative to initial object?

(o) Draw a diagram showing location of lenses, objects and images

Solutions

Expert Solution

genius_generous answered 1 month ago

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