Question

In: Physics

1.20cm tall object is 50.0cm to the left of a diverging lens (lens 1) of focal...

1.20cm tall object is 50.0cm to the left of a diverging lens (lens 1) of focal length of magnitude 40.0cm. A second converging lens (lens 2) of focal length 60.0cm, is located 300cm to the right of the first lens along the same optic axis.

(a)Calculate the location of the image (call it I1) formed by the lens1.

(b) Is image I1 real or virtual?

(c) Is image I1 on left side or right side of lens 1?

(d) Calculate magnification m1 of lens 1. Is image I1 upright or inverted?

(e) Calculate height of the image I1.

(f) I1 is now the object for the second lens. Is the object for lens 2 real or virtual?

(g) Calculate the object distance for lens 2?

(h) Calculate the location of the image I2 produced by lens2.

(i) Calculate magnification m2 of lens2. Is image I2 upright or inverted?

(j) Calculate height of the image I2.

(k) Find overall magnification of these two lens system.

(l) Is final image real or virtual?

(m) Is final image upright or inverted, relative to initial object?

(n) Is final image enlarged or reduced in size, relative to initial object?

(o) Draw a diagram showing location of lenses, objects and images

Expert Solution

genius_generous answered 8 months ago

A 1.8-cm-tall object is 3.1 cm to the left of a diverging lens with a focal...

A 1.8-cm-tall object is 3.1 cm to the left of a diverging lens with a focal length of -3.1 cm. A converging lens with a focal length of 4.6 cm is distance d to the right of the first lens. a) For what value of d is the image at infinity? b) What is the angular size of the image as seen by looking through the converging lens? ?c) What is the angular magnification of this two-lens magnifier?

A 1.4-cm-tall object is located 3.0cm to the left of a converging lens with a focal...

A 1.4-cm-tall object is located 3.0cm to the left of a converging lens with a focal length of 4.0cm . A diverging lens, of focal length -7.4cm, is 14cm to the right of the first lens. Find the position of the final image. s2` = -5.7 cm Find the size of the final image. h2` = ? Find the orientation of the final image. a) real, upright b) real, inverted c) virtual, upright d) virtual, inverted

A 1.0-cm-tall object is 100 cm from a screen. A diverging lens with focal length -20...

A 1.0-cm-tall object is 100 cm from a screen. A diverging lens with focal length -20 cm is 20 cm in front of the object. a. What is the focal length of a second lens that will produce a well-focused, 2.0-cm-tall image on the screen? b. What is the distance from the screen of the second lens?

An object is placed 12 cm in front of a diverging lens with a focal length...

An object is placed 12 cm in front of a diverging lens with a focal length of 7.9 cm. (a) Find the image distance and determine whether the image is real or virtual. (b) Find the magnification

Problem 1) A 5 cm tall object is 20 cm in front of a diverging lens...

Problem 1) A 5 cm tall object is 20 cm in front of a diverging lens with a focal length of 10 cm. a) What is the location of the image? -6.67cm b) What is the height of the image? -1.67 cm c) The image is:virtual d) The image is:upright At 15 cm to the right of the lens in problem 1 we add a converging lens with a focal length of 10 cm. a) What is the location of...

An object is 15.2 cm to the left of a lens with a focal length of...

An object is 15.2 cm to the left of a lens with a focal length of 10.2 cm. A second lens of focal length 11.8 cm is 39.27 cm to the right of the first lens. The height of the object of is 2.1 cm. What is the location of the final image with respect to the second lens? What is the height of the image?

A diverging lens has a focal length of -30.0cm. Located the images for object distances of...

A diverging lens has a focal length of -30.0cm. Located the images for object distances of (a) 60.0cm (b) 30.0cm (c) 15.0cm. What kind of images are they (real or virtual; upright or inverted)? (d) Draw a ray diagram for part (a).

An object is placed 22.7 cm to the left of a diverging lens (f = -13.0...

An object is placed 22.7 cm to the left of a diverging lens (f = -13.0 cm). A concave mirror (f = 9.99 cm) is placed 29.9 cm to the right of the lens to form an image of the first image formed by the lens. Find the final image distance, measured relative to the mirror. (b) Is the final image real or virtual? (c) Is the final image upright or inverted with respect to the original object?

An object is placed 27.2 cm to the left of a diverging lens (f = -10.6...

An object is placed 27.2 cm to the left of a diverging lens (f = -10.6 cm). A concave mirror (f = 17.1 cm) is placed 40.3 cm to the right of the lens to form an image of the first image formed by the lens. Find the final image distance, measured relative to the mirror. (b) Is the final image real or virtual? (c) Is the final image upright or inverted with respect to the original object?

1. A 3.0cm tall object is located 5.0cm from a converging lens that has a focal...

1. A 3.0cm tall object is located 5.0cm from a converging lens that has a focal length of 10.0cm. What is the magnification of the image? a. M= 0.500 b. M= -0.500 c.M= 2.0 d. M= -2.0 e. none of the above 2. A bird is flying above the water when it spots a fish a few meters ahead in a direction about 30 degrees below the horizontal (the bird is not directly over the fish). The bird is hungry,...