In: Statistics and Probability
The value of a sports franchise is directly related to the amount of revenue that a franchise can generate. Below is the data that represents the value (in $millions) and the annual revenue (in $millions) for 30 Major League Baseball franchises. Suppose you want to develop a simple linear regression model to predict franchise value based on annual revenue generated.
Team |
Revenue |
Value |
Baltimore |
179 |
460 |
Boston |
310 |
1000 |
Chicago White Sox |
214 |
600 |
Cleveland |
178 |
410 |
Detroit |
217 |
478 |
Kansas City |
161 |
354 |
Los Angeles Angels |
226 |
656 |
Minnesota |
213 |
510 |
New York Yankees |
439 |
1850 |
Oakland |
160 |
321 |
Seattle |
210 |
585 |
Tampa Bay |
161 |
323 |
Texas |
233 |
674 |
Toronto |
188 |
413 |
Arizona |
186 |
447 |
Atlanta |
203 |
508 |
Chicago Cubs |
266 |
879 |
Cincinnati |
185 |
424 |
Colorado |
193 |
464 |
Houston |
196 |
549 |
Los Angeles |
230 |
1400 |
Miami |
148 |
450 |
Milwaukee |
195 |
448 |
New York Mets |
225 |
719 |
Philadelphia |
249 |
723 |
Pittsburgh |
168 |
336 |
St. Louis |
233 |
591 |
San Diego |
163 |
458 |
San Francisco |
230 |
643 |
Washington |
200 |
480 |
(a ) Use the least-squares method to determine the regression coefficients (intercept and slope).
(b) Interpret the meaning of the intercept and slope in this problem.
(c) Predict the value of a baseball franchise that generates $150 million of annual revenue.
Using Excel<data<megastat<correlation/regression<regression
Regression Analysis | ||||||
r² | 0.790 | |||||
r | 0.889 | |||||
Std. Error | 150.955 | |||||
n | 30 | |||||
k | 1 | |||||
Dep. Var. | Value y | |||||
ANOVA table | ||||||
Source | SS | df | MS | F | p-value | |
Regression | 24,04,121.3683 | 1 | 24,04,121.3683 | 105.50 | 5.31E-11 | |
Residual | 6,38,045.3317 | 28 | 22,787.3333 | |||
Total | 30,42,166.7000 | 29 | ||||
Regression output | confidence interval | |||||
variables | coefficients | std. error | t (df=28) | p-value | 95% lower | 95% upper |
Intercept | -496.3022 | 110.71 | -4.48 | 0.00 | -723.09 | -269.51 |
Revenue x | 5.1961 | 0.5059 | 10.271 | 5.31E-11 | 4.1599 | 6.2324 |
a)
Intercept (b0) -496.3022
Slope (b1) 5.1961
b)
A practical interpretation of the Y-intercept,b0, is not meaningful because no value is going to have a revenue of zero. The slope,b1, implies that for each increase of 1 million dollars in annual revenue, the value is expected to increase by the value of b1, in millions of dollars.
c)
Y=5.196 x-496.302 = 5.196*150-496.302=283.098
Please do the comment for any doubt or clarification. Please upvote if this helps you out. Thank You!