Question

In: Chemistry

For the reaction 2NO_2 (g)→2NO_2 (g)+O_2 (g) The data given below was collected: Time(s) [NO2] Ln[NO2]...

For the reaction 2NO_2 (g)→2NO_2 (g)+O_2 (g)

The data given below was collected:

Time(s)	[NO2]	Ln[NO2]	1/[NO2]
0	0.110	-2.205	9.066
1	0.108	-2.229	9.294
2	0.105	-2.254	9.524
3	0.103	-2.277	9.747

Obtain the average rate of decomposition of NO_2 in units of M/s for each interval.

What is the order of the reaction with respect to NO_2?

How long would it take for the concentration to decrease to .0900M?

Expert Solution

2 NO2 (g) -----------------> 2 NO + O2

1)

average rate = change in concentration / change in time

= 0.110 - 0.108 / 1 - 0

= 0.002 M/s

average rate = 0.108 - 0.105 / 2-1

= 0.003 M/s

average rate = 0.105 - 0.103 / 3-2

= 0.002 M/s

2)

from the given data

the order is zero order .

the rate constant is = 2.3 x 10^-3 M/s

3)

t = (0.110 - 0.09) / k

= (0.110 - 0.09) / 2.3 x 10^-3

= 8.7 sec

time = 8.7 sec

queen_honey_blossom answered 3 years ago

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