In: Statistics and Probability
3) Suppose you wanted to simulate possible profit outcomes, and you know that revenues have a 30% likelihood of being $2 million, 12% likelihood of being $3.5 million, 48% likelihood of being $4 million, and 10% likelihood of being $4.5 million.
Furthermore, Costs have a 30% probability of being $3.25 million and a 70% probability of being $3.5 million.
Using Excel, simulate 100 instances of profit. Calculate average, minimum, and maximum profits.
Is 100 instances sufficient? Why or why not?
Revenue LIkelihood is let say x then
x | P(x) |
2 | 0.3 |
3.5 | 0.12 |
4 | 0.48 |
4.5 | 0.1 |
Sum | 1 |
Cost is let say y then probability distribution
y | P(y) |
3.25 | 0.3 |
3.5 | 0.7 |
Sum | 1 |
Profit P = X - Y
so we will simuate it 100 times and following is the result. Screenshow of excel image in given below
We will use Data analysis -> Random Number Generationmethod to solve the problem.
Revenue | Cost | Profit |
3.5 | 3.5 | 0 |
2 | 3.5 | -1.5 |
4 | 3.5 | 0.5 |
4.5 | 3.25 | 1.25 |
3.5 | 3.5 | 0 |
2 | 3.25 | -1.25 |
2 | 3.5 | -1.5 |
2 | 3.5 | -1.5 |
4 | 3.25 | 0.75 |
2 | 3.25 | -1.25 |
4 | 3.25 | 0.75 |
4 | 3.5 | 0.5 |
4 | 3.5 | 0.5 |
2 | 3.25 | -1.25 |
2 | 3.5 | -1.5 |
2 | 3.5 | -1.5 |
4 | 3.5 | 0.5 |
4 | 3.25 | 0.75 |
4 | 3.5 | 0.5 |
4 | 3.25 | 0.75 |
4 | 3.5 | 0.5 |
4 | 3.5 | 0.5 |
4 | 3.5 | 0.5 |
4 | 3.5 | 0.5 |
3.5 | 3.25 | 0.25 |
4 | 3.5 | 0.5 |
2 | 3.25 | -1.25 |
4 | 3.5 | 0.5 |
2 | 3.25 | -1.25 |
4 | 3.5 | 0.5 |
2 | 3.5 | -1.5 |
4 | 3.5 | 0.5 |
4 | 3.5 | 0.5 |
4.5 | 3.5 | 1 |
4 | 3.25 | 0.75 |
4 | 3.5 | 0.5 |
2 | 3.5 | -1.5 |
4 | 3.5 | 0.5 |
4 | 3.25 | 0.75 |
4 | 3.5 | 0.5 |
4 | 3.5 | 0.5 |
4 | 3.5 | 0.5 |
4 | 3.5 | 0.5 |
2 | 3.5 | -1.5 |
2 | 3.5 | -1.5 |
2 | 3.5 | -1.5 |
2 | 3.5 | -1.5 |
2 | 3.5 | -1.5 |
4 | 3.5 | 0.5 |
2 | 3.25 | -1.25 |
4 | 3.5 | 0.5 |
4 | 3.25 | 0.75 |
4 | 3.5 | 0.5 |
4 | 3.5 | 0.5 |
2 | 3.25 | -1.25 |
4 | 3.5 | 0.5 |
3.5 | 3.5 | 0 |
2 | 3.25 | -1.25 |
2 | 3.25 | -1.25 |
4.5 | 3.5 | 1 |
2 | 3.25 | -1.25 |
4.5 | 3.25 | 1.25 |
4 | 3.5 | 0.5 |
4 | 3.25 | 0.75 |
4 | 3.25 | 0.75 |
4 | 3.5 | 0.5 |
3.5 | 3.5 | 0 |
4 | 3.5 | 0.5 |
2 | 3.5 | -1.5 |
4 | 3.5 | 0.5 |
4 | 3.5 | 0.5 |
4.5 | 3.5 | 1 |
2 | 3.5 | -1.5 |
3.5 | 3.5 | 0 |
3.5 | 3.25 | 0.25 |
4 | 3.5 | 0.5 |
4 | 3.25 | 0.75 |
4 | 3.25 | 0.75 |
3.5 | 3.25 | 0.25 |
2 | 3.25 | -1.25 |
2 | 3.5 | -1.5 |
4 | 3.25 | 0.75 |
4.5 | 3.5 | 1 |
4 | 3.5 | 0.5 |
2 | 3.5 | -1.5 |
4 | 3.5 | 0.5 |
2 | 3.25 | -1.25 |
2 | 3.5 | -1.5 |
4 | 3.5 | 0.5 |
4.5 | 3.5 | 1 |
4 | 3.5 | 0.5 |
4 | 3.5 | 0.5 |
3.5 | 3.25 | 0.25 |
2 | 3.5 | -1.5 |
2 | 3.5 | -1.5 |
4.5 | 3.5 | 1 |
3.5 | 3.25 | 0.25 |
4 | 3.5 | 0.5 |
4 | 3.5 | 0.5 |
2 | 3.5 | -1.5 |
Average Profit = -0.0725 million dollars
Minimum Profit = -1.5 milllion dollars
Maximum Profit = 1.25 million dollars
Here the sample size of 100 simulation is insufficient as we get the averaeg profit negative but as we calculate expected profit by using probability distribution, we get a position result.
so it should be higher.