Question

In: Statistics and Probability

A quality control expert at LIFE batteries wants to test their new batteries. The design engineer...

A quality control expert at LIFE batteries wants to test their new batteries. The design engineer claims they have a variance of 8464 with a mean life of 886 minutes. If the claim is true, in a sample of 145 batteries, what is the probability that the mean battery life would be greater than 904.8 minutes? Round your answer to four decimal places.

Solutions

Expert Solution

µ = 886

sd = sqrt(8464) = 92

n = 145

                              

                               = P(Z > 2.46)

                               = 1 - P(Z < 2.46)

                               = 1 - 0.9931

                               = 0.0069


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