In: Statistics and Probability
A quality control expert at LIFE batteries wants to test their new batteries. The design engineer claims they have a variance of 8464 with a mean life of 886 minutes. If the claim is true, in a sample of 145 batteries, what is the probability that the mean battery life would be greater than 904.8 minutes? Round your answer to four decimal places.
µ = 886
sd = sqrt(8464) = 92
n = 145
= P(Z > 2.46)
= 1 - P(Z < 2.46)
= 1 - 0.9931
= 0.0069