In: Statistics and Probability
A quality control expert at Glotech computers wants to test their new laptop monitors. The production manager claims the monitors have a mean life of 89 months with a population standard deviation of 5 months. If the claim is true, what is the probability that the mean monitor life would be greater than 87.8 months in a sample of 123 monitors? Round your answer to four decimal places.
A. 0.5948
B. 0.0001
C. 0.9961
D. 0.5000
E. 0.0039
Solution :
Given that ,
mean = = 89
standard deviation = = 5
= / n = 5/ 123 = 0.4508
P( > 87.8) = 1 - P( < 87.8)
= 1 - P[( - ) / < (87.8 - 89) / 0.4508]
= 1 - P(z < -2.66)
= 1 - 0.0039
= 0.9961
Probability = 0.9961