Question
In: Statistics and Probability
An operation manager at an electronics company wants to test their amplifiers. The design engineer claims...
An operation manager at an electronics company wants to test their amplifiers. The design engineer claims they have a mean output of 495 watts with a standard deviation of 12 watts.
What is the probability that the mean amplifier output would be greater than496.1 watts in a sample of 88 amplifiers if the claim is true? Round your answer to four decimal places.
Solutions
Expert Solution
Solution :
Given that,
mean = 
= 495
standard deviation = 
= 12
n = 88
= = 495
=
/ 
n = 12 /
88 = 1.28
P( > 496.1) = 1 - P(
< 496.1)
= 1 - P[(
-
) /
< (496.1 - 495) /1.28 ]
= 1 - P(z < 0.86)
Using z table,
= 1 - 0.8051
= 0.1949
orchestra answered 2 years agoRelated Solutions
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