In: Statistics and Probability
A quality control expert at Glotech computers wants to test their new monitors. The production manager claims they have a mean life of 73 months with a standard deviation of 7 months.
If the claim is true, what is the probability that the mean monitor life would be greater than 72.1 months in a sample of 109 monitors? Round your answer to four decimal places.
Solution :
Given that ,
mean =
= 73
standard deviation =
= 7
n = 109
=
= 73
=
/
n = 7 /
109 = 0.6705
P(
> 72.1 ) = 1 - P(
<72.1 )
= 1 - P[(
-
) /
< (72.1 - 73) / 0.6705]
= 1 - P(z <-1.34)
= 1 - 0.0901 = 0.9099
probability 0.9099