In: Statistics and Probability
A cannot have occurred. What is the likelihood of either Event A or Event B occurring?
(a)
Given:
P(A) =0.45
P(B) = 0.35
Events A and B are mutually exclusive.
By Addition Theorem of Probability of Mutually Exclusive Events,
we get:
P(A + B) = P(A) + P(B)
= 0.45 + 0.35
= 0.80
So, Answer is:
0.80
(b)
Let
A = getting exactly 1 Head in 2 coins
B = getting a number of divisible by 5 of 20 sided die
To find P(A) = P(getting exactly 1 Head in 2 coins):
Number of events:
{HH,HT,TH,TT}: 4 Nos.
Favorable events:
{HT,TH}: 2 Nos.
So,
P(A) = P(getting exactly 1 Head in 2 coins):= 2/4 = 0.50
To find P(B)= P( getting a number of divisible by 5 of 20 sided die)
Number of events = 20
Favorable events:
{0,5,10,15,20}: 5 Nos.
So,
P(B)= P( getting a number of divisible by 5 of 20 sided die) = 5/20 = 0.25
By Multiplication Theorem of Probability of Independent Events,
we get:
P(AB) = P(A) X P(B)
= 0.50 X0.25
= 0.125
So, Answer is:
0.125
(c)
Using probability terms, we would describe the events in (a) as Mutually Exclusive Events.
Using probability terms, we would describe the events in (b) as Independent Events.