Question

In: Physics

Two loudspeakers emit sound waves along the x-axis. A listener in front of both speakers hears...

Two loudspeakers emit sound waves along the x-axis. A listener in front of both speakers hears a maximum sound intensity when speaker 2 is at the origin and speaker 1 is at x = 0.450 m . If speaker 1 is slowly moved forward, the sound intensity decreases and then increases, reaching another maximum when speaker 1 is at x = 0.850 m.

A.What is the frequency of the sound? Assume vsound =340m/s.

B. What is the phase difference between the speakers?

Solutions

Expert Solution

In the first case, the path difference between the two speakers is
  
And in the 2nd case, the path difference between the two speakers is
  
As in both cases, the intensity is maximum, so, the difference between these two path difference is equal to the wavelength of the sound. i.e.,
   
  
  
  
And as the speed of the sound is
   
A)
so, the frequency of the sound is
   
  

B)
  The phase difference in the first case, when the path difference is 0.450 m, is given by
  
  
  
  
And in the 2nd case, when the path difference is 0.850 m, the phase difference is given by
   
  
  
  

genius_generous answered 3 months ago
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