Question

In: Operations Management

Twelve samples, each containing five parts, were taken from a process that produces steel rods at...

Twelve samples, each containing five parts, were taken from a process that produces steel rods at Emmanuel Kodzi’s factory. The length of each rod in the samples was determined. The results were tabulated and sample means and ranges were computed. The results were:

SAMPLE SAMPLE MEAN (IN.) RANGE (IN.)
1 10.02 0.011
2 10.02 0.014
3 9.991 0.007
4 10.006 0.022
5 9.997 0.013
6 9.999 0.012
7 10.001 0.008
8 10.005 0.013
9 9.995 0.004
10 10.001 0.011
11 10.001 0.014
12 10.006 0.009

a) Determine the upper and lower control limits and the overall means for x -charts and R -charts.

b) Draw the charts and plot the values of the sample means and ranges.

c) Do the data indicate a process that is in control? d) Why or why not?

i AM HAVING ISSUES WITH THE FORMULAS TO MAKE SENSE FOR Standard Deviation, SO IF YOU CAN EXPLAIN THE FORMULAS IN EACH CELL ON HOW YOU GOT THE ANSWER THAT WOULD BE HELPFUL. THANK YOU

Solutions

Expert Solution

Range (Max- Min) X-bar= average of sample
0.011 10.020
0.014 10.020
0.007 9.991
0.022 10.006
0.013 9.997
0.012 9.999
0.008 10.001
0.013 10.005
0.004 9.995
0.011 10.001
0.014 10.001
0.009 10.006
0.012 10.004
R-bar (Average of above values) X-bar-bar (average of above values)

D4, D3 and A2 are taken from table of factors computing 3 sigma control limits, sample size= 5

D4 (n=5)= 2.115
D3 (n=5)= 0
control limits for Range,
CL or R-bar= 0.012
UCL=R-bar*D4 0.024
LCL=R-bar*D3 0.000
A2 is taken from table of factors
A2 (n=5) 0.577
control limits for X bar,
CL or Xbarbar 10.004
UCL=Xbarbar+ (A2)*Rbar 10.010
LCL=Xbarbar- (A2)*Rbar 9.997

b:

The process Mean is out of control: As we can see that NO sample is beyond control limits in Mean chart

R chart

The process range is in control: As we can see that NO sample is beyond control limits in Range chart


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