In: Statistics and Probability
Is there a relation between incidents of child abuse and number of runaway children? A random sample of cities (over 10,000 population) gave the following information about the number of reported incidents of child abuse and the number of runaway children. (Reference: Federal Bureau of Investigation, U.S. Department of Justice.)
City | 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | 9 | 10 | 11 | 12 | 13 | 14 | 15 |
Abuse cases | 56 | 21 | 78 | 63 | 58 | 103 | 98 | 17 | 18 | 25 | 61 | 41 | 31 | 118 | 11 |
Runaways | 410 | 249 | 757 | 629 | 518 | 706 | 604 | 263 | 404 | 291 | 514 | 416 | 335 | 674 | 436 |
Use a 1% level of significance to test the claim that there is a monotone-increasing relationship between the ranks of incidents of abuse and number of runaway children.
(a) Rank-order abuse using 1 as the largest data value. Also rank-order runaways using 1 as the largest data value. Then construct a table of ranks to be used for a Spearman rank correlation test.
City | Abuse Cases Rank x |
Runaways Rank y |
d = x - y | d2 |
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 |
Σd2 = |
(b) What is the level of significance?
State the null and alternate hypotheses.
Ho: ρs > 0; H1: ρs = 0Ho: ρs = 0; H1: ρs > 0 Ho: ρs = 0; H1: ρs < 0Ho: ρs = 0; H1: ρs ≠ 0
(c) Compute the sample test statistic. (Use 3 decimal
places.)
(d) Find the P-value interval of the sample test
statistic.
P-value < ---Select--- 0.001 0.01 0.05
0.10
(e) Conclude the test.
At the α = 0.01 level, we reject the null hypothesis and conclude the data are not statistically significant.At the α = 0.01 level, we fail to reject the null hypothesis and conclude the data are not statistically significant. At the α = 0.01 level, we reject the null hypothesis and conclude the data are statistically significant.At the α = 0.01 level, we fail to reject the null hypothesis and conclude the data are statistically significant.
(f) Interpret your conclusion in the context of the
application.
Fail to reject the null hypothesis, there is sufficient evidence
that a monotonic increasing relationship exists between incidents
of child abuse and run-away children.
Fail to reject the null hypothesis, there is insufficient evidence
that a monotonic increasing relationship exists between incidents
of child abuse and run-away children.
Reject the null hypothesis, there is sufficient evidence that a
monotonic increasing relationship exists between incidents of child
abuse and run-away children.
Reject the null hypothesis, there is insufficient evidence that a
monotonic increasing relationship exists between incidents of child
abuse and run-away children.
part A)
Abuse cases |
Runnway |
Abuses cases rank |
Runnways rank |
d |
d.square |
56 |
410 |
8 |
10 |
-2 |
4 |
21 |
249 |
12 |
15 |
-3 |
9 |
78 |
757 |
4 |
1 |
3 |
9 |
63 |
629 |
5 |
4 |
1 |
1 |
58 |
518 |
7 |
6 |
1 |
1 |
103 |
706 |
2 |
2 |
0 |
0 |
98 |
604 |
3 |
5 |
-2 |
4 |
17 |
263 |
14 |
14 |
0 |
0 |
18 |
404 |
13 |
11 |
2 |
4 |
25 |
291 |
11 |
13 |
-2 |
4 |
61 |
514 |
6 |
7 |
-1 |
1 |
41 |
416 |
9 |
9 |
0 |
0 |
31 |
335 |
10 |
12 |
-2 |
4 |
118 |
674 |
1 |
3 |
-2 |
4 |
11 |
436 |
15 |
8 |
7 |
49 |
total |
94 |
part B)
Part C) sample test statistic rho =0.8321429
part D) p-value = 0.0001578
therefore p-value <0.001
part E)
At the α = 0.01 level, we reject the null hypothesis and conclude the data are statistically significant.
part F)
Reject the null hypothesis, there is sufficient evidence that a monotonic increasing relationship exists between incidents of child abuse and run-away children.
Note : for part a) i used excel to compute the given table while part b and c I use r command as follows
Abuse_cases=c(56, 21, 78, 63, 58, 103, 98, 17, 18, 25, 61, 41, 31, 118, 11)
Runaways=c(410, 249, 757, 629, 518, 706, 604, 263, 404, 291, 514, 416, 335, 674, 436)
cor.test(Abuse_cases,Runaways,method = "spearman")
Spearman's rank correlation rho
data: Abuse_cases and Runaways
S = 94, p-value = 0.0001578
alternative hypothesis: true rho is not equal to 0
sample estimates:
rho
0.8321429