A string with a length of 35 cm is fixed at both ends. Waves travel along...

A string with a length of 35 cm is fixed at both ends. Waves travel along it at a speed of 4 m/s.

What is the frequency of its lowest mode of standing waves?

At what distance from the end of the string is the first node if the string is vibrating at four times its fundamental frequency?

Solutions

Expert Solution

The lowest standing wave frequency is called the fundamental or first harmonic. The wavelength of the fundamental is twice the length of the string.

Given is:-

length of the string is = 35cm or 0.35m

the speed of the waves = 4m/s

Therefore the fundamental wavelength

and the frequency of lowest mode of standing waves is

If the string is vibrated 4 times it's fundamental frequency, then the new frequency will be

then the new fundamental wavelength is

then the first node will be at half distance of this wavelength

therefore

first node distance from the end of the string is = or

genius_generous answered 1 year ago

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