Question

In: Physics

A string 4.40 m long is held fixed at both ends. If a sharp blow is...

A string 4.40 m long is held fixed at both ends. If a sharp blow is applied to the string at its center, it takes 0.0400 s for the pulses to travel to the ends of the string and return to the middle.

a)What is the lowest standing wave frequency for this string?

b)What is the second lowest standing wave frequency for this string?

Expert Solution

(a)

The lowest standing wave frequency(or fundamental frequency) of the string is given by the expression

The velocity of the sound can be deterimed using the kinematic euqation

Now, the acceleration of the pulse can be found using the equation

Hence, the velocity of the sound on the string is given by

Now, the fundamental frequency of the string is

Therefore, the lowest standing wave frequency of the string is 25 Hz.

(b)The second lowest standing wave frequency for this string is equal to th first harmonic.

Therefore, the second lowest standing wave frequency for this string is 50 Hz.

genius_generous answered 3 years ago

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