In: Statistics and Probability
A supplier submits lote of fabric to a textile manufacturer. The customer wants to know if the lot average breaking strength exceeds 200 psi. If so, he wants to accpt the lot. Past experience indicates that a reasonable value for the variance of breaking strength is 100 (psi)2.. Four specimens are randomly selected and the average breaking strength observed is 214 psi. Perform a hypothesis test (7 step procedure outlined in class). Perform the test using the Fixed significance level test and the P-Value approach test and state your decision.
Step 1:
H0: Null Hypothesis: 200 ( the lot average breaking strength does not exceed 200 psi.)
Step 2:
HA: Alternative Hypothesis: 200 ( the lot average breaking strength exceeds 200 psi.) (Claim)
Step 3:
Take Significance Level = = 0.05
From Table, critical value of Z = 1.64
Step 4:
n = 4
= 214
=
Step 5:
Test Statistic is given by:
Step 6:
Rejection Region:
Reject H0 if Z > 1.64
Step 7:
Since calculated value of Z = 2.80 is greater than critical value of Z= 1.64, the difference is significant. Reject null hypothesis.
Step 8:
Conclusion::
The data support the claim that the lot average breaking strength
exceeds 200 psi.
P Value approach:
By Technology, p - value = 0.0026.
Since p - value =0.0026 is less than = 0.05, the difference is significant. Reject null hypothesis.
Conclusion::
The data support the claim that the lot average breaking strength
exceeds 200 psi.