In: Math
Use the sample information x¯ ⎯ x¯ = 40, σ = 7, n = 13 to calculate the following confidence intervals for μ assuming the sample is from a normal population.
(a) 90 percent confidence. (Round your
answers to 4 decimal places.)
The 90% confidence interval is from __to__
(b) 95 percent confidence. (Round your
answers to 4 decimal places.)
The 95% confidence interval is from __to__
(c) 99 percent confidence. (Round your
answers to 4 decimal places.)
The 99% confidence interval is from __to__
(d) Describe how the intervals change as you
increase the confidence level.
A- The interval gets narrower as the confidence level increases.
B- The interval gets wider as the confidence level decreases.
C- The interval gets wider as the confidence level increases.
D- The interval stays the same as the confidence level increases.
Solution :
Given that,
= 40
= 7
n = 13
a ) At 90% confidence level the z is ,
= 1 - 90% = 1 - 0.90 = 0.10
/ 2 = 0.10 / 2 = 0.05
Z/2
= Z0.05 = 1.645
Margin of error = E = Z/2*
(
/n)
= 1.645 * ( 7 /
13)
= 3.19
At 90% confidence interval estimate of the population mean is,
- E <
<
+ E
40 - 3.19 <
< 40 + 3.19
36.81<
< 43.19
b) At 95% confidence level the z is ,
=
1 - 95% = 1 - 0.95 = 0.05
/ 2 = 0.05 / 2 = 0.025
Z/2
= Z0.025 = 1.960
Margin of error = E = Z/2*
(
/n)
= 1.960 * ( 7 /
13)
= 3.80
At 95% confidence interval estimate of the population mean is,
- E <
<
+ E
40 - 3.80 <
< 40 + 3.80
36.20<
< 43.80
c ) At 99% confidence level the z is ,
= 1 - 99% = 1 - 0.99 = 0.01
/ 2 = 0.01 / 2 = 0.005
Z/2
= Z0.005 = 2.576
Margin of error = E = Z/2*
(
/n)
= 2.576 * ( 7 /
13)
= 5.00
At 99% confidence interval estimate of the population mean is,
- E <
<
+ E
40 - 5.00<
< 40 + 5.00
35.00<
< 45.00
d ) Option c ) is correct.
The interval gets wider as the confidence level increases.