Question
In: Chemistry
What mass (in grams) of cobalt(II) nitrate hexahydrate is needed to make 100.0mL of 0.10M cobalt(II)...
What mass (in grams) of cobalt(II) nitrate hexahydrate is needed to
make 100.0mL of 0.10M cobalt(II) nitrate solution?
Solutions
Expert Solution
moles of cobalt(II) nitrate solution = molarity x volume
= 0.10 x 100 / 1000
= 0.01
Molecular Weight cobalt(II) nitrate hexahydrate = 291.03 g / mol
moles = mass / molar mass
mass = moles x molar mass
= 0.01 x 291.03
= 2.91 g
mass of cobalt(II) nitrate hexahydrate = 2.91 g
queen_honey_blossom answered 2 years agoRelated Solutions
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The following question deals with nickel(II) nitrate
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hexahydrate?
b) What is the molar mass of nickel(II) nitrate hexahydrate?
c) What is the concentration of a nickel(II) nitrate stock
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d) What is the concentration of a dilute nickel(II) nitrate
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Calculate the mass (in mg) of solid chromium(III) nitrate needed to make 250. mL of an...
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3.0 mg
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What mass in grams of a 10.0% by mass aqueous silver nitrate solution must be added...
What mass in grams of a 10.0% by mass aqueous silver nitrate
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What mass in grams of a 10.0% by mass aqueous silver nitrate solution must be added...
What mass in grams of a 10.0% by mass aqueous silver nitrate
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0.0250 M in chromium (II) chloride and 0.0200 M in chromium (III)
chloride to precipitate all chloride ion as silver chloride from
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a)What is the mass (in grams) of the solid product when 7.5 g of silver nitrate...
a)What is the mass (in grams) of the solid product when 7.5 g of
silver nitrate reacts in solution with excess sodium
carbonate?AgNO3(aq) + Na2CO3(aq)
--> Ag2CO3(s) + NaNO3(aq)
[unbalanced]
b)What is the mass (in grams) of the precipitate when 7.62 g of
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1- Solid cobalt(II) nitrate is slowly added to 150 mL of a 0.0337 M potassium sulfide...
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2- Solid nickel(II) nitrate is slowly added to
175 mL of a 0.0657 M
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Water is Unusual because...(Choose All true)
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-Most molecules as small as water are gases at room
temperature
-most molecules as small as water have higher boiling points
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3. What is the mass (in grams) of the precipitate when 6.85 g of
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4. What is the theoretical yield (in grams) of the precipitate
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