Question
In: Chemistry
3. What is the mass (in grams) of the precipitate when 6.85 g of iron(II) chloride...
3. What is the mass (in grams) of the precipitate when 6.85 g of iron(II) chloride reacts in solution with excess sodium phosphate?
4. What is the theoretical yield (in grams) of the precipitate when 10.75 g of iron(II) nitrate reacts in solution with 20.84 g sodium phosphate?
5. What volume (in L) of hydrogen gas (density = 0.0902 g/L) is needed to fully react with 20.57 g of copper(I) chloride in solution?
Solutions
queen_honey_blossom answered 2 years agoRelated Solutions
What precipitate forms when aqueous soulutions of Potassium Chloride, Sodium Sulfide, Iron(II) Nitrate are simultaneously mixed?...
What precipitate forms when aqueous soulutions of Potassium
Chloride, Sodium Sulfide, Iron(II) Nitrate are simultaneously
mixed? Show the molecular and net ionic equation for the
reaction.
What is the mass of the precipitate formed when 207.86 mL of 0.250 M barium chloride...
What is the mass of the precipitate formed when 207.86 mL of 0.250
M barium chloride is added to 150.00 mL of a 1.750 M sulfuric acid
solution?
1) For the following reaction, 50.6 grams of iron(II) chloride are allowed to react with 127...
1) For the following reaction, 50.6 grams of
iron(II) chloride are allowed to react with
127 grams of silver nitrate
.
iron(II) chloride(aq) +
silver
nitrate(aq) iron(II)
nitrate(aq) + silver
chloride(s)
What is the maximum amount of iron(II) nitrate
that can be formed?______ grams
What is the FORMULA for the limiting
reagent?
What amount of the excess reagent remains after the reaction is
complete? ____ grams
2) For the following reaction, 21.7 grams of
iron are allowed to react with
33.9...
1) For the following reaction, 50.6 grams of iron(II) chloride are allowed to react with 127...
1) For the following
reaction, 50.6 grams of iron(II)
chloride are allowed to react with 127
grams of silver nitrate .
iron(II) chloride(aq) +
silver nitrate(aq)
iron(II) nitrate(aq) +
silver chloride(s)
What is the maximum amount of iron(II) nitrate
that can be formed?_____________ grams
What is the
FORMULA for the limiting reagent?
What amount of the excess reagent remains after the reaction is
complete? _______________grams
2) For the following
reaction, 21.7 grams of iron are
allowed to react with 33.9...
What mass of precipitate is formed when 135.00ml .25 M calcium chloride is reacted with 145.00...
What mass of precipitate is formed when 135.00ml .25 M calcium
chloride is reacted with 145.00 ml of .55M potassium sulfate?
Answer: 4.6 g
1)For the following reaction, 4.56 grams of iron(II) chloride are mixed with excess silver nitrate. The...
1)For the following reaction, 4.56 grams of iron(II) chloride
are mixed with excess silver nitrate. The reaction yields 5.35
grams of iron(II) nitrate. iron(II) chloride (aq) + silver nitrate
(aq) iron(II) nitrate (aq) + silver chloride (s) What is the
theoretical yield of iron(II) nitrate ? grams What is the percent
yield of iron(II) nitrate ? %
2) For the following reaction, 6.19 grams of iron are mixed with
excess oxygen gas . The reaction yields 5.24 grams of iron(II)...
Magnesium reacts with iron (II) Chloride to form magnesium chloride and iron. A mixture of 41.0g...
Magnesium reacts with iron (II) Chloride to form magnesium
chloride and iron. A mixture of 41.0g of magnesium and 175 g of
iron (II) chloride is allowed to react. Identify the limiting
reactant and determine the mass of the excess reactant.
1. What mass of water is needed to dissolve 43.5 g of copper (II) chloride to...
1.
What mass of water is needed to dissolve 43.5 g of copper (II)
chloride to prepare a 0.521 molal solution?
2. Calculate the boiling point of a solution made from 224 g
of magnesium chloride dissolved in 625 g of water. kb= 0.512
degrees celsius/m
Iron reacts with chlorine gas to form iron (III) chloride. How many grams of iron(III) chloride...
Iron reacts with chlorine gas to form iron (III)
chloride. How many grams of iron(III) chloride are formed from 112g
of iron?
Wondering if I did this right!
First balance: 3Fe + Cl ---> FeCl3 or 3Fe +
3Cl ---> FeCl3 *Not Sure*
Second Convert grams to mols: 112g/Fe to Mols =
2 mol/fe
Third Convert mols to gram: 2 mol/Fe *
162.204g/FeCl3 / 3 mol/Fe = 108.136 g/FeCl/3 round
108grams/FeCl3
Please do and let me know if this correct!...
A mixture consisting of only chromium(II) chloride (CrCl2, 122.90 g/mol) and iron(III) chloride (FeCl3, 162.20 g/mol)...
A mixture consisting of only chromium(II) chloride
(CrCl2, 122.90 g/mol) and iron(III) chloride
(FeCl3, 162.20 g/mol) weighs 2.3738 g. When the mixture
is dissolved in water and an excess of silver acetate is added, all
the chloride ions associated with the original mixture are
precipitated as insoluble silver chloride (AgCl, 143.32 g/mol). The
mass of the silver chloride is found to be 5.7101 g. Calculate the
mass percentage of chromium(II) chloride in the original
mixture.
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