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Flu cases this past flu season in the Remulak school system (n = 500) were 15...

  1. Flu cases this past flu season in the Remulak school system (n = 500) were 15 per week. For the entire state, the weekly average was 16, and the standard deviation was 15.1. Are the kids in Remulak as sick as the kids throughout the state?
  2. The night-shift workers in three of Super Bo's specialty stores stock about 500 products in about 3 hours. How does this rate compare with the stocking done in the other 97 stores in the chain, which average about 496 products stocked in 3 hours? Are the stockers at the specialty stores doing a “better than average” job? Here's the info that you need:

Solutions

Expert Solution

Answer:

1.

Given,

Mean = = 16

= 15

Standard deviation = = 15.1

n = 500

Null hypothesis Ho : = 16

Alternative hypothesis Ha : 16

Now to give test statistic

z = ( - ) / ( / sqrt(n))

substitute the given values

z = (15 - 16) / (15.1/sqrt(500))

= - 1 / 0.675292529

z = - 1.48

Now let us consider,

significance level = 0.05

Here for 0.05 level of significance , Zalpha/2 = +/- 1.96 [since from z table]

So here we can say that |z| < Z

i.e.,

Hence we fail to reject Ho at 0.05 level of significance

So we conclude that the kids in remulak are as sick as kids throughout the state.


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