Question

In: Statistics and Probability

Flu cases this past flu season in the remulak school system n=500 were 15 per week.


Flu cases this past flu season in the remulak school system n=500 were 15 per week. for the entire state, the weekly average was 16, and the standard deviation was 15.1. are the kids in remulak as sick as the kids throughout the state.

Solutions

Expert Solution

Given       
μ = 16 Population Mean      
σ= 15.1 Population Standard Deviation      
X̅ = 15 Sample Mean      
n =500 Sample Size      
Let α = 0.05 Level of significance      
        
Since the population standard deviation is known, we use the z-test       
The null and alternative hypothesis are       
Ho : μ = 16       
H1 : μ ≠ 16 … (Since we have to test if the kids in remulak as sick as the kids throughout the state.)      
        
Find Calculated Value of test statistic z       
           
Test statistic z-calc = -1.4808       
This is a double sided z-test       
p-value for the test is found using Excel function NORM.S.DIST       
p-value = 2 * NORM.S.DIST(-1.4808, TRUE)       
p-value = 0.1387       
        
Since 0.1387 > 0.05       
that is p-value > α       
we DO NOT reject Ho       
Conclusion       
The kids in remulak are as sick as the kids throughout the state.      


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