Question
In: Statistics and Probability
13. In a survey of 500 males ages 20 to 24, 15.8% were neither in school...
13. In a survey of 500 males ages 20 to 24, 15.8% were neither in school nor working. In a survey of 500 females ages 20 to 24, 17.8% were neither in school nor working. At a = 0.05, can you support the claim that the proportion of males ages 20 to 24 who were neither in school nor working is less than the proportion of females ages 20 to 24 who were neither in school nor working?
Solutions
orchestra answered 1 year agoRelated Solutions
In a random sample 100 people ages 20 to 24, 25% said they were smokers. In...
In a random sample 100 people ages 20 to 24, 25% said
they were smokers. In a random sample of 300 people ages 25 to 29,
51 of them said they were smokers. Test the claim that the
proportion of smokers in the two age groups is the same. Use a
significance level of 0.05. Provide the following.
a. the null and alternative hypothesis
b. the test statistic
c. the p-value
d. the final conclusion in nontechnical terms
e. construct...
According to a study, 45% of all males between the ages of 18 and 24 live...
According to a study, 45% of all males between the ages of 18
and 24 live at home. (Unmarried college students living in a dorm
are counted as living at home.) Suppose that a survey is
administered and 118 of 223 respondents indicated that they live at
home.
(a) Use the normal approximation to the binomial to approximate
the probability that at least 118
respondents live at home.
(b) Do the results from part (a) contradict the study?
in a random sample of 500 people aged 20-24, 110 were smokers. in a random sample...
in
a random sample of 500 people aged 20-24, 110 were smokers. in a
random sample of 450 people aged 25-29, 65 were smokers. test the
claim that the proprtion of smokers age 20-24 is higher than the
proportion of smokers age 25-29. use a significance level of 0.01.
please show work!
In a survey of 625 males ages 18-64, 393 say they have gone to the dentist...
In a survey of 625 males ages 18-64, 393 say they have gone to
the dentist in the past year.
Construct 90% and 95% confidence intervals for the population
proportion. Interpret the results and compare the widths of the
confidence intervals. If convenient, use technology to construct
the confidence intervals.
The 90% confidence interval for the population
proportion p is (______,_____). (Round to three
decimal places as needed.)
The 95% confidence interval for the population
proportion p is (_____,______).(Round to...
12. In a survey of 645 males ages 18-64, 394 say they have gone to the...
12. In a survey of 645 males ages 18-64, 394 say they have gone
to the dentist in the past year. Construct 90% and 95% confidence
intervals for the population proportion. Interpret the results and
compare the widths of the confidence intervals. If convenient, use
technology to construct the confidence intervals.
The 90% confidence interval for the population proportion p is
( nothing, nothing). (Round to three decimal places as
needed.)
The 95% confidence interval for the population proportion p...
In a survey of 636 males ages 18-64, 399 say they have gone to the dentist...
In a survey of 636 males ages 18-64, 399 say they have gone to
the dentist in the past year.
Construct 90% and 95% confidence intervals for the population
proportion. Interpret the results and compare the widths of the
confidence intervals. If convenient, use technology to construct
the confidence intervals.
In a survey of 633 males ages? 18-64, 394 say they have gone to the dentist...
In a survey of 633 males ages? 18-64, 394 say they have gone to
the dentist in the past year.
Construct? 90% and? 95% confidence intervals
for the population proportion.
Interpret the results and compare the widths of the confidence
intervals.
In a survey of 600 males ages 18-64, 392 say they have gone to the dentist...
In a survey of 600 males ages 18-64, 392 say they have gone to
the dentist in the past year. Construct 90% and 95% confidence
intervals for the population proportion. Interpret the results and
compare the widths of the confidence intervals.
If convenient, use technology to construct the confidence
intervals. The 90% confidence interval for the population
proportion p is (_,_) (Round to three decimal places as
needed.)
In a survey of 609609 males ages 18-64, 397397 say they have gone to the dentist...
In a survey of 609609 males ages 18-64, 397397 say they have
gone to the dentist in the past year. Construct 90% and 95%
confidence intervals for the population proportion. Interpret the
results and compare the widths of the confidence intervals. If
convenient, use technology to construct the confidence intervals.
The 90% confidence interval for the population proportion p is
(nothing,nothing). (Round to three decimal places as
needed.)
In a survey of 609609 males ages 18-64, 397397 say they have gone to the dentist...
In a survey of
609609
males ages 18-64,
397397
say they have gone to the dentist in the past year.
Construct 90% and 95% confidence intervals for the population
proportion. Interpret the results and compare the widths of the
confidence intervals. If convenient, use technology to construct
the confidence intervals.
The 90% confidence interval for the population proportion p
is
(nothing,nothing).
(Round to three decimal places as needed.)
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