Question

In: Physics

You pick up two dice, shake them around, and then over the course of 0.08 seconds...

You pick up two dice, shake them around, and then over the course of 0.08 seconds throw them horizontally over a table, providing them with horizontal speeds of 0.6 and 0.5 m/s respectively. If the mass of each die is 3 grams, with what total force did you supply to the dice? (Consider that this is also the total force exerted back upon your hand by the dice.)

Report the value in millinewtons rounded to the nearest whole number.

Expert Solution

Mass of each die is m=3g=0.003kg

Initial velocity of both dice is v_1i=v_2i=0

Final velocity of dice 1 is v_1f=0.6m/s

Final velocity of dice 2 is v_2f=0.5m/s

Initial momentum of both dices is zero, because their initial velocities are zero.

Final momentum of dice 1 is

Final momentum of dice 2 is

Force is equal to the rate of change of momentum. Force on dice 1 is

The change takes place in 0.08s

Force on dice 2 is

The change takes place in 0.08s

Total force supplied to the dice is

Using 10^-3N=1mN

genius_generous answered 2 years ago

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