One liter of an ideal monatomic gas (gamma=5/3) at atmospheric pressure (1.0 atm) and a temperature...

One liter of an ideal monatomic gas (gamma=5/3) at atmospheric pressure (1.0 atm) and a temperature of 300K is used in the following cycle: an adiabatic compression to one half its original volume, followed by a constant-volume cooling to 300K, followed by an isothermal expansion back to original volume. Determine the work done by the gas, the heat entering the gas and the change in thermal energy of the gas in each leg of the cycle. Organize answer in table. is this cycle allowed by the second law of thermodynamics? what kind of heat machine does this cycle represent? heat engine? refrigerator? explain

Expert Solution

during adiabatic process T₁V₁^-1 = T₂V₂^-1

T₂ =300*(2)^2/3 = 476.4k

work done in adiabatic process is W = nR / - 1( T₁ - T₂ )

W = $\left [$ 8.314 / 22.4 ( 5/3 -1) $\left \right ]$ ( 300-476.4)

W = -98.2 J

work done in isothermal process W =2.303nRT ( v₂ / v₁ )

W = 77.18J

the heat entering the gas Q = W = 77.18J

this cycle is not allowed the second law of thermodynamics

it is a refrigerator

genius_generous answered 5 months ago

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