In: Physics
during adiabatic process
T1V1-1 =
T2V2
-1
T2 =300*(2)2/3 = 476.4k
work done in adiabatic process is W = nR / - 1(
T1 - T2 )
W = 8.314 /
22.4 ( 5/3 -1)
( 300-476.4)
W = -98.2 J
work done in isothermal process W =2.303nRT (
v2 / v1 )
W = 77.18J
the heat entering the gas Q = W = 77.18J
this cycle is not allowed the second law of thermodynamics
it is a refrigerator