The average human body contains 5.00 L of blood with a Fe2+ concentration of 2.10×10^−5 M...

The average human body contains 5.00 L of blood with a Fe2+ concentration of 2.10×10^−5 M . If a person ingests 5.00 mL of 14.0 mM NaCN, what percentage of iron(II) in the blood would be sequestered by the cyanide ion?

Expert Solution

queen_honey_blossom answered 4 months ago

The average human body contains 5.70 L of blood with a Fe2+ concentration of 2.10×10−5M ....

The average human body contains 5.70 L of blood with a Fe2+ concentration of 2.10×10−5M . If a person ingests 10.0 mL of 25.0 mM NaCN, what percentage of iron(II) in the blood would be sequestered by the cyanide ion? Express the percentage numerically.

The average human body contains 5.50 L of blood with a Fe2+ concentration of 2.20×10−5 M...

The average human body contains 5.50 L of blood with a Fe2+ concentration of 2.20×10−5 M . If a person ingests 9.00 mL of 21.0 mM NaCN, what percentage of iron(II) in the blood would be sequestered by the cyanide ion?

The average human body contains 5.10 L of blood with a Fe2+ concentration of 3.20×10−5 M...

The average human body contains 5.10 L of blood with a Fe2+ concentration of 3.20×10−5 M . If a person ingests 11.0 mL of 25.0 mM NaCN, what percentage of iron(II) in the blood would be sequestered by the cyanide ion?

The average human body contains 6.50 L of blood with a Fe2+ concentration of 2.50×10^−5 M...

The average human body contains 6.50 L of blood with a Fe2+ concentration of 2.50×10^−5 M . If a person ingests 12.0 mL of 17.0 mM NaCN, what percentage of iron(II) in the blood would be sequestered by the cyanide ion? For example, the iron(II) ion, Fe2+Fe2+, can combine with the cyanide ion, CN−CN−, to form the complex [Fe(CN)6]4−[Fe(CN)6]4− according to the equation Fe2+(aq)+6CN−(aq)⇌[Fe(CN)6]4−(aq)Fe2+(aq)+6CN−(aq)⇌[Fe(CN)6]4−(aq) where Kf=4.21×10^45 This reaction is what makes cyanide so toxic to human beings and other animals....

1) The average human body contains 5.70 L of blood with a Fe2+ concentration of 2.60×10−5...

1) The average human body contains 5.70 L of blood with a Fe2+ concentration of 2.60×10−5 M . If a person ingests 12.0 mL of 16.0 mM NaCN, what percentage of iron(II) in the blood would be sequestered by the cyanide ion? (When species combine to produce a coordination complex, the equilibrium constant for the reaction is called is the formation constant, Kf. For example, the iron(II) ion, Fe2+, can combine with the cyanide ion, CN−, to form the complex...

The average human body contains 6.30 L of blood with a Fe2+ concentration of 1.60×10−5M ....

The average human body contains 6.30 L of blood with a Fe2+ concentration of 1.60×10−5M . If a person ingests 9.00 mL of 13.0 mM NaCN, what percentage of iron(II) in the blood would be sequestered by the cyanide ion?

A 1.00 L solution contains 5.00x106-5 M Cu(NO3)2 and 1.00x10^-3 M ethylenediamine. What is the concentration...

A 1.00 L solution contains 5.00x106-5 M Cu(NO3)2 and 1.00x10^-3 M ethylenediamine. What is the concentration of Cu2+ (aq) in the solution

Red blood cells have an average lifespan of 120 days in the human body. If a...

Red blood cells have an average lifespan of 120 days in the human body. If a given individual produces 200 billion red blood cells per day, what is the average number of red bloods cells in his/her body? (Note: 1 trillion = 1000 billion) SHOW WORK a) 1.6 trillion cells b) 8 trillion cells c) 16 trillion cells d) 24 trillion cells e) 30 trillion cells f) 600 trillion cells g) We do not have enough information to answer this...

A solution of Na2CO3 is added dropwise to a solution that contains 1.15×10−2 M Fe2+ and...

A solution of Na2CO3 is added dropwise to a solution that contains 1.15×10−2 M Fe2+ and 1.58×10−2 M Cd2+. What concentration of CO32− is need to initiate precipitation? Neglect any volume changes during the addition.

A 6.0 L waste solution in the lab contains F- at a concentration of 0.1045 M,...

A 6.0 L waste solution in the lab contains F- at a concentration of 0.1045 M, but the disposal concentration limit for this anion is 1.3 mM. To reduce the concentration to the legal limit you decide to precipitate most of the fluoride by the addition of MgCl2 (molar mass=95.21 g/mol). A) what will be the equilibrium molar concentration of Mg2+ needed to reduce the [F-] concentration to 1.3 mM? B) what total mass of MgCl2 is needed to precipice...

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