The average human body contains 5.70 L of blood with a Fe2+ concentration of 2.10×10−5M ....

The average human body contains 5.70 L of blood with a Fe2+ concentration of 2.10×10⁻⁵M . If a person ingests 10.0 mL of 25.0 mM NaCN, what percentage of iron(II) in the blood would be sequestered by the cyanide ion?

Express the percentage numerically.

Expert Solution

queen_honey_blossom answered 1 year ago

The average human body contains 6.30 L of blood with a Fe2+ concentration of 1.60×10−5M ....

The average human body contains 6.30 L of blood with a Fe2+ concentration of 1.60×10−5M . If a person ingests 9.00 mL of 13.0 mM NaCN, what percentage of iron(II) in the blood would be sequestered by the cyanide ion?

1) The average human body contains 5.70 L of blood with a Fe2+ concentration of 2.60×10−5...

1) The average human body contains 5.70 L of blood with a Fe2+ concentration of 2.60×10−5 M . If a person ingests 12.0 mL of 16.0 mM NaCN, what percentage of iron(II) in the blood would be sequestered by the cyanide ion? (When species combine to produce a coordination complex, the equilibrium constant for the reaction is called is the formation constant, Kf. For example, the iron(II) ion, Fe2+, can combine with the cyanide ion, CN−, to form the complex...

The average human body contains 5.50 L of blood with a Fe2+ concentration of 2.20×10−5 M...

The average human body contains 5.50 L of blood with a Fe2+ concentration of 2.20×10−5 M . If a person ingests 9.00 mL of 21.0 mM NaCN, what percentage of iron(II) in the blood would be sequestered by the cyanide ion?

The average human body contains 5.10 L of blood with a Fe2+ concentration of 3.20×10−5 M...

The average human body contains 5.10 L of blood with a Fe2+ concentration of 3.20×10−5 M . If a person ingests 11.0 mL of 25.0 mM NaCN, what percentage of iron(II) in the blood would be sequestered by the cyanide ion?

The average human body contains 6.50 L of blood with a Fe2+ concentration of 2.50×10^−5 M...

The average human body contains 6.50 L of blood with a Fe2+ concentration of 2.50×10^−5 M . If a person ingests 12.0 mL of 17.0 mM NaCN, what percentage of iron(II) in the blood would be sequestered by the cyanide ion? For example, the iron(II) ion, Fe2+Fe2+, can combine with the cyanide ion, CN−CN−, to form the complex [Fe(CN)6]4−[Fe(CN)6]4− according to the equation Fe2+(aq)+6CN−(aq)⇌[Fe(CN)6]4−(aq)Fe2+(aq)+6CN−(aq)⇌[Fe(CN)6]4−(aq) where Kf=4.21×10^45 This reaction is what makes cyanide so toxic to human beings and other animals....

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